x^2+4x+5=(x+2)(x+7)

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Solution for x^2+4x+5=(x+2)(x+7) equation: 



x^2+4x+5=(x+2)(x+7)

We move all terms to the left:

x^2+4x+5-((x+2)(x+7))=0

We multiply parentheses ..

x^2-((+x^2+7x+2x+14))+4x+5=0



We calculate terms in parentheses: -((+x^2+7x+2x+14)), so:

(+x^2+7x+2x+14)

We get rid of parentheses

x^2+7x+2x+14

We add all the numbers together, and all the variables

x^2+9x+14

Back to the equation:

-(x^2+9x+14)



We add all the numbers together, and all the variables

x^2+4x-(x^2+9x+14)+5=0

We get rid of parentheses

x^2-x^2+4x-9x-14+5=0

We add all the numbers together, and all the variables

-5x-9=0

We move all terms containing x to the left, all other terms to the right

-5x=9

x=9/-5

x=-1+4/5

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